What is the equation of the line that passes through the point (3,-3) and has a slope of 0?

given us,

slope= 0

(x1y1)= (3,-3)

here

(y-y1) =m(x-x1)

or, (y+3)=0(x-3)

or (y+3)= x-3

or, x+y= -3-3

x+y= -6

Step-by-step explanation:

x+y= -6

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47