Find the area of the region bounded by the curves y equals the inverse sine of x divided by 2 , y = 0, and x = 2 obtained by integrating with respect to y. Your work must include the definite integral and the antiderivative

answer: sorry but i need points

step-by-step explanation:

so what is the question

step-by-step explanation:

answer: howdy

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)