A polynomial equation of degree three, p(x), is used to model the volume of a rectangular box. The graph of p(x) has x-intercepts at (-2, 0), (10, 0), and (14, 0).

Consider the following statements:

I. The equation of p(x) = (x – 2)(x + 10)(x + 14).

II. The equation of p(x) = (x + 2)(x – 10)(x – 14).

III. The maximum volume occurs when x = 10.

IV. The volume of the box is 0 when x = 10.

Which of the statements regarding p(x) could be TRUE?

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

18.8cm hope i at all

step-by-step explanation:

c-   36

taxicab circle radius 9 has 4(9) = 36 points

the answer to this is a. a^2 + b^2 = c^2