HURRY 65 POINTS consider the reduction of the rectangle.

A larger rectangle has a length of 18 inches and width of 8 inches. A smaller rectangle has a length of x inches and width of 3 inches.

Write a proportion and then solve to find the missing measure of the reduced rectangle.

What two ratios can be used in the proportion?

What is the value of the missing measure?

18/8 = x/3

x = 6.75 inches (length)

Step-by-step explanation:

A larger rectangle has a length of 18 inches and width of 8 inches.

Inches /width = 18/8

So, for a rectangle that has a length of x inches and width of 3 inches the ratio is :

x/3

Solving for x:

18/8 = x/3

18/8 (3) =x

6.75 in= x

Feel free to ask for more if needed or if you did not understand something.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

answer:

what is your question that you ask

step-by-step explanation: