What is the equation, in point-slope form, for the line with a SLOPE of -2 that passes through the point of (1,-4)? Group of answer choices

y - 4 = -2(x + 1)

y+ 4 = -2(x - 1)

y + 4 = 2(x - 1)

y - 4 = 2(x + 1)

y+4=-2(x-1)

Step-by-step explanation:

Formula

y-y1=m(x-x1)

y-(-4)=-2(x-(1))

y+4=-2(x-1)

26?

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.