Parallel lines, transversal, and algebra really need help

1. 58 = 5x-2, 60 = 5x, x = 12

2. 134 = 16x+22, 112 = 16x, x = 7

3. 125 = 7x-1, 126 = 7x, x = 18

4. 133+9x+2 = 180, 9x=45, x=6

5. 8x-77 = 3x+38, 5x = 115, x=23

6. 11x-47 = 6x-2, 5x = 45, x=9

7. 13x-21 = 5x+75, 8x = 96, x=12

8. 5x+3+9x-33 = 180, 14x = 210, x=15

9. 8x-31 = 6x+3, 2x = 34, x=17

5y+35+6(17)+3 = 180, 5y = 40, y = 8

10. 29x-3+15x+7 = 180, 44x = 176, x=4

13y-17+15(4)+7 = 180, 13y = 130, y=10

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet