Sapphire and Abe are shelving books at a public library. Sapphire shelves 12 books at a time, whereas Abe shelves 18 at a time. If they end up shelving the same number of books, what is the smallest number of books each could have shelved.

36

Step-by-step explanation:

Given:  Sapphire shelves 12 books at a time, whereas Abe shelves 18 at a time.

If they end up shelving the same number of books, what is the smallest number of books each could have shelved = LCM (12,18)

12 = 2 x 2 x 3

18 = 2 x 3 x 3

LCM (12, 18) = 2 x 2 x 3 x 3 = 36

Hence, the smallest number of books each could have shelved = 36

dont know

step-by-step explanation:

there is no points to select.

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