Owen made exactly 72% of his free throws during the first half of the basketball season, and he made six free throws during the second half of the season. For the entire season he made exactly 60% of his free throws. What is the fewest possible number of free throws Owen could have attempted during the second half of the season?

The fewest possible number of free throws Owen attempted is 15 throws

Step-by-step explanation:

From the first half,

72% = 72/100 = 18/25, reduced to its simplest ratio.

It means that he made at least 18 free throws in the first half of the season.

From the second half,

Let x be the fewest possible outcome of free throws, and the sum of total is 60% = 60/100 = 0.6

Considering the 6 free throws during the second half of the season,

(18+6)/(25+x) = 0.6

24/(25+x) = 0.6

Solving for x,

24 = 0.6(25+x)

24 = 15+0.6x

24-15 = 0.6x

9 = 0.6x

x = 9/0.6 = 15

x = 15 free throws

The fewest possible number of free throws Owen attempted is 15 throws

no, because the sides are not congruent