Leshonda had been working at her job for almost twenty years. She felt like she worked overtime more often than not (more than 50% of the time) and deserved a raise, so she randomly selected 50 paychecks (each for one week of work) and found that she had worked overtime in 32 of those weeks. Use a TI-83, TI-83 plus, or TI-84 calculator to test whether Leshonda worked overtime more often than not. Identify the p-value, rounding to three decimal places.

Z statistic = 1.980

Pvalue = 0.024

Step-by-step explanation:

Sample size (n) = number of paychecks = 50

Number of overtime (x) = 32

Let Number of overtime = o

Claim : Overtime work is done more than 50% of the time ;

Null hypothesis:H0: o = 0.5

Alternative hypothesis : H1: o > 0.5

Using the T84 calculator :

Selecting the 1 proportion test under the Stat menu:

p0 = 50% = 0.5

x = 32 ; n = 50 ; >p0

The z test statistic value obtained is 1.980 (3 decimal places)

The P value = 0.024 (3 decimal places)

At α = 0.05 ;

P value < α ; therefore we reject the null

Hence, overtime work is done more than 50% of the time.

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