Write the equation of the line perpendicular to y=4/3x+1 that passes through the points (-8, 4).

The equation is;

y = -3/4x + 12

Step-by-step explanation:

The general form for the equation of a straight line is;

y = mx + b

where m is the slope and b is the y-intercept

With respect to this question;

4/3 is the slope and 1 is the intercept

If two lines are perpendicular, then the product of their slopes is -1

Mathematically;

4/3 * m2 = -1

m2 = -3/4

So to find the equation of this second line, we use the point slope form

This is;

y-y1 = m(x-x1)

y-4 = -3/4(x + 8)

y- 4 = -3/4x + 8

y = -3/4x + 12

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.