The sizes of the angles in degrees of the quadrilateral are x+10
2x
x+30
x+80

a) use this information to write down and equation in terms of x
b) use your answer to part a to work out the size of the smallest angle of the quadrilateral

5x+120

Step-by-step explanation:

first you add the 2x x and x and x that would get you 5x and then add the 20 and 10 and 80 that would get you 120

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.

-5, your answer was correct