I'm confused, how would I do this? Write a function in the form y = mx + b for the line that passes
through the points (2, 4) and (6, 16).

Y=3x-2 i believe is the answer i did y2-y1 divided by x2-x1 which is 16-4 divided by 6-2 and 16-4 is 12 and 6-2 is 4 and 12/4 is 3 so 3 is your slope (m) so to find b you chose either (2,4) or (6,16) either one will work and i chose (6,16) then your plug in 16 for y and 6 for x so your equation is 16=3(6)+b then 3(6) is 18 so your new equation is 16=18+b then you subtract 18 from both sides to isolate b and 16-18 is -2 so your final equation is y=3x-2 you can do the same thing with the (2,4) point and end up with the same answer