Pls answeer provide evidence as well:)

No, the relation of hours of study time to grade earned on a test is not a function because there cannot be more than one output for one input. Also, the graph of the points doesn't pass the vertical line test.

Step-by-step explanation:

In order for something to be classified as a function, it needs to follow two rules:

1. There can only be one output for a certain input.

Although different inputs can have the same output, one input can't have more than one output. In this problem, the input 6 has two outputs: 75 and 82. So, the relation is not a function.

2. The graph of the points has to pass the vertical line test.

First, take the points from the table and graph them. These points are:

(4, 75), (6, 75), and (6, 82).

The vertical line test states that if a vertical line drawn on the graph intersects the graph more than once, then the graph isn't a function. In this case, a vertical line can be drawn at x = 6. This line ends up intersecting two points: (6, 75) and (6, 82). Since the vertical line intersected the graph at two points, the graph of the relation isn't a function.

let f (x ) is a function and c be a positive real number,   the graph of the function g (x ) = f (cx ) is represented as follows.

when, c > 1,   the function compresses it in the x - direction.

when, 0 < c < 1, the function stretches it.

the function is g ( x ) = (9x )2.

the heighest power of x in g ( x ) = (9x )2 is 2, so the parent function is square function.

the equation of parent function is f ( x ) = x 2 .

the function is g ( x ) = (9x )2 and the parent function is f ( x ) = x 2 .

so, the functions f and g have the following relationship.

g ( x ) = f ( 9x ).

compare the function g ( x ) = f ( 9x ) with g (x ) = f (cx ).

c = 9 ( > 1 ).

so, the function g (x ) = (9x )2 compresses it in the x - direction.

step-by-step explanation:

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: