PLS HELP WILL GIVE BRAINLIEST What are 3 different methods for solving systems of equations and when would you use each one? (10 pts)

How do you graph the solution set to a system of linear inequalities in two variables? (10 pts)

How do you determine if a system of linear equations has one solution, no solutions or infinitely many solutions? (10 pts)

Step-by-step explanation:

     graphing.

substitution method.

elimination method.

We will use as an example the following system of inequalities:

3x +2y ≥ 5x -4

y < (1/2)x +3

For each inequality, do the following:

1. If it is not this way already, arrange the inequality so that each variable appears on only one side of the inequality. Putting the inequality into any of the standard forms will do this. It will be helpful later if you arrange the inequality so that at least one variable has a positive coefficient. (You may have to multiply by -1 (and change the sense of the inequality) to do this.)

Our example inequalities are now ...

-2x +2y ≥ -4 . . . . . or divide by 2 to get . . . . -x +y ≥ -2

y < (1/2)x +3

2. Notice the inequality symbol, and whether it includes the "or equal to" case.

the first inequality is ≥, so includes "or equal to"

the second inequality is <, so does not include "or equal to"

3. Replace the inequality symbol with an equal sign and graph the resulting equation. If the "or equal to" case is included, the line is graphed as a solid line. If it is not, then the line is graphed as a dashed line.

the first equation (-x +y = -2) is graphed with a solid line

the second equation (y = (1/2)x +3) is graphed with a dashed line

4. It is not necessary, but is less confusing, to choose a variable in the inequality (after step 1) that has a positive coefficient. Notice whether this variable is "less than" or "greater than" the stuff on the other side of the inequality.

y ≥ . . . . for the first inequality

y < . . . or . . . x > . . . . for the second inequality

If it is less than, shade the portion of the graph below (for y <) or to the left (for x <) of the line you graphed in step 3.

the second inequality has y < , so the graph will be shaded below the dashed line. It also has x > , so will be shaded to the right of the dashed line. (These are the same shading.)

If it is greater than, shade the portion of the graph above (for y >) or to the right (for x >) of the line you graphed in step 3.

the first inequality has y ≥ , so the graph will be shaded above the solid line.

5. The solution set is where the shaded areas overlap. Any point on a dashed line is not in the solution set.

The graph for the example inequalities is attached. The first one is graphed and shaded in red; the second one is graphed and shaded in blue.

A system has no solutions if the lines are parallel. When solving the system, if you get a false statement (a number equal to a different number) this means there are no solutions.

1. Substitution, elimination & graphing.

Substitution is best to use when an equation has already been isolated; for example, y = x+4. The equation can then be substituted into the other to solve the system.

Elimination is faster to use when equations would be difficult to isolate. For example, 3x+2y=5 and -3x+5y=18 would be easily eliminated because of how you solve with that method.

Graphing is a good option; it works best when both equations are already in a graphable form, like y=mx+b.

2. To find the solution to a system of linear inequalities, graph both lines. Then, pay close attention to the inequality sign. If it’s less than, you shade below the line & greater than you shade above the line. The solution will be the region where the two lines overlap.

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation: