A solution contains 11 pints of antifreeze and seven pints of water . How many pints Of water must be added to 77 pints Of antifreeze to get a solution with the same concentration. Please help me with question I don’t get it.

49 pints of water

Step-by-step explanation:

that's the answer to the question

49 pints

Step-by-step explanation: if they had 11pints of the anti freeze. And they multiplied it by 7 to get to 77! Therefore you take the multiplier that they used which was 7 and us it to the 7 pints. So then you will be multiplying 7x7 which would be 49.

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant