In an aquarium, there are 3 red, 6 yellow, 4 white and 2 black fish. Find the ratio of the: a) Number of yellow fish to the number of white fish. b) Number of black fish to the total number of fish. c) Number of red fish to the number of black fish.

a. 3 : 2

b. 2 : 15

c. 3 : 2

Step-by-step explanation:

Red fish = 3

Yellow fish = 6

White fish = 4

Black fish = 2

Total number of fishes = 15

a) Ratio of the Number of yellow fish to the number of white fish.

Yellow fish : White fish

6 : 4

= 6 /4

= 3/2

= 3 : 2

Ratio of the Number of yellow fish to the number of white fish = 3 : 2

b) Ratio of the Number of black fish to the total number of fish

Black fish : Total fish

2 : 15

= 2 / 15

= 2 : 15

Ratio of the Number of black fish to the total number of fish = 2 : 15

c) Ratio of the Number of red fish to the number of black fish

Red fish : black fish

= 3 : 2

= 3/2

= 3 : 2

Ratio of the Number of red fish to the number of black fish = 3 : 2

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204