Calcium-41 is being used in studies testing the effectiveness of drugs for preventing osteoporosis. The half-life of calcium-41 is 100,000 years. If 20 grams of calcium-41 are present initially, how long would it take until only 2 grams remains?

332,193 years

Step-by-step explanation:

From the question above, we are to calculate the time in an half life question, hence, the formula is given as

t = In(Nt/No) ÷ -(In2/t½)

Where

t = time is takes for an substance to decay or reduce

Nt = Amount of sample after time = 2g

No = Initial amount of sample = 20g

t½ = Half life = 100,000 years

Hence,

t = In(2/20) ÷ (In 2/ 100,000)

t = 332192.80948874 years

Approximately = 332,193 years

a) 0.25x times 3. (could be wrong on equation.)

b) 2.25 pound of dark chocolate. (can i eat all the chocolate? plz? anyway, again, could be wrong, but i hope im right. all the chocolate together should be 5.25 pounds)

have a good day!