Find all zeros (real and complex) of the same function
f(x) = 24 ++ 7x2 + 9x - 18

x = (i sqrt(87))/14 - 9/14 or x = 1/14 (-i) sqrt(87) - 9/14

Step-by-step explanation:

Solve for x:

7 x^2 + 9 x + 6 = 0

Hint: | Write the quadratic equation in standard form.

Divide both sides by 7:

x^2 + (9 x)/7 + 6/7 = 0

Hint: | Solve the quadratic equation by completing the square.

Subtract 6/7 from both sides:

x^2 + (9 x)/7 = -6/7

Hint: | Take one half of the coefficient of x and square it, then add it to both sides.

Add 81/196 to both sides:

x^2 + (9 x)/7 + 81/196 = -87/196

Hint: | Factor the left hand side.

Write the left hand side as a square:

(x + 9/14)^2 = -87/196

Hint: | Eliminate the exponent on the left hand side.

Take the square root of both sides:

x + 9/14 = (i sqrt(87))/14 or x + 9/14 = 1/14 (-i) sqrt(87)

Hint: | Look at the first equation: Solve for x.

Subtract 9/14 from both sides:

x = (i sqrt(87))/14 - 9/14 or x + 9/14 = 1/14 (-i) sqrt(87)

Hint: | Look at the second equation: Solve for x.

Subtract 9/14 from both sides:

x = (i sqrt(87))/14 - 9/14 or x = 1/14 (-i) sqrt(87) - 9/14

50- 250 is correct i did that one too

step-by-step explanation: