GENERATE THE FIRST 4 Terms of f(n)=-2(n-1)+8

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8, 6, 4, 2

Step-by-step explanation:

f(n)=-2(n-1)+8

Plug n =1

f(1)=-2(1-1)+8 = - 2*0+8 = 0+ 8 = 8

Plug n =2

f(1)=-2(2-1)+8 = - 2*1+8 = - 2+ 8 = 6

Plug n =3

f(1)=-2(3-1)+8 = -2*2+8 = -4+ 8 = 4

Plug n =4

f(1)=-2(4-1)+8 = -2*3+8 = -6+ 8 = 2

the answer

b. they are parallel and will never intersect.

3 is greater then both of those numbers