tugboat A and tugboat B are pulling a barge. each tugboat is connected to the barge via a cable. if the length of the cables are 63 meters an 68 meters and the tugboats are 35 meters apart, find the angle formed

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

$9.41

step-by-step explanation:

answer: -1

step-by-step explanation:

the answer would be c:   ax + b = ax + c

step-by-step explanation: