![\sqrt[3]{\frac{y^{2}}{y^{\frac{4}{5}}}} =\sqrt[3]{y^({2-\frac{4}{5})}} \\\\=\sqrt[3]{y^{\frac{6}{5}}}\\\\=(y^{\frac{6}{5}})^{\frac{1}{3}} \\\\=y^{\frac{6}{5}*\frac{1}{3}}\\\\= y^{\frac{2}{5}}](/tpl/images/0946/9237/a3cd6.png)
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