Solve the initial value problem. dy
= csc(x), y(1) = -6
dx
Select one:
O a. y = {x'csc (t) dt – 6
O b. none of these
O c. y = | csc (t) dt + 1
O d. y = ls' -csc (t) dt – 6
O e. y = Jcsc (1) dt – 6

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

i would need to see the shape

step-by-step explanation: