A country's population in 1993 was 204 million. In 2000 it was 208 million. Estimate
the population in 2015 using the exponential
growth formula. Round your answer to the
nearest million. HURRY PLEASEE

Step-by-step explanation:To solve the exponential growth application question we proceed as follows;

suppose the time, t between 1993 to 2000 is such that in 1993, t=0 and in 2000, t=7.

Note theta the population is in millions;

The exponential formula is given by:

f(t)=ae^(kt)

where;

f(t) =current value

a=initial value

k=constant of proportionality

t=time

substituting the values we have in our formula we get:

132=127e^(7k)

132/127=e^(7k)

introducing the natural logs we get:

ln (132/127)=7k

k=[ln(132/127)]/7

k=0.0055

Thus our formula will be:

f(t)=127e^(0.0055t)

The population in 2008 will be:

f(t)=127e^(15*0.0055)=127e^(0.0825)=137.922

Thus the population in 2008 is appropriately 138 million.

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4