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Mathematics, 04.12.2020 06:40 lexidecker243

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The path of a ball is given by y = – 1/20x^2 + 4x + 6 where y is the height of the ball as a function of the horizontal distance from where the ball was
thrown.
Part A:
Find the maximum height of the ball.
Part B
Tell me which of the numbers in the original equation gives the height of the ball before it got throwed ( was thrown).
Part C:
If that number were to change, how would it affect the coordinates (remember their are two) of the point at which the ball reaches its maximum point?


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The path of a ball is given b

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