The number of swimmers at a city pool on Monday was twice the number who were there on Tuesday. The number at the pool on Wednesday was 11 fewer than 3 times the number on Tuesday. The total swimmers for all 3 days were 625. How many swimmers were at the pool each day? Define a variable, write an equation, and solve the problem.

102 1/3 swimmers

Step-by-step explanation:

Let

Number of swimmers on Tuesday = x

Number of swimmers on Monday = 2x

Number of swimmers on Wednesday = 3x - 11

Total swimmers for all 3 days = 625

x + 2x + (3x - 11) = 625

3x + 3x - 11 = 625

6x = 625 - 11

6x = 614

x = 614 / 6

= 102 2/6

x = 102 1/3 swimmers

Number of swimmers on Tuesday = x = 102 1/3 swimmers

Number of swimmers on Monday = 2x

= 2(102 1/3)

= 204 2/3

Number of swimmers on Wednesday = 3x - 11

=3(102 1/3) - 11

= 307 - 11

= 296

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)