Mathematics, 04.12.2020 16:50 puppylover72
(1 point) Let f be a periodic function of period 10 such that f(x)=x2 for −5≤x<5. Then the Fourier series of f is
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![=\frac{1}{10} (\frac{x^3}{3})^{5}_{-5}\\\\=\frac{1}{30}[5^3+5^3]\\\\=\frac{2}{30}(125)\\\\=\frac{1}{15} \times 125\\\\=\frac{25}{3}](/tpl/images/0949/8185/7f498.png)
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(1 point) Let f be a periodic function of period 10 such that f(x)=x2 for −5≤x<5. Then the Fourie...
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