Please come and help me with this! Best Answer get Brainliest :D Please number your responses to the questions as they are shown (1a, 1b)

a. Create a quadratic expression in standard form.

b. Rewrite the expression by completing the square. Explain your work using complete sentences.

A = Solve 5x2 + 6x + 1 = 0

B= Coefficients are:a = 5, b = 6, c = 1

Quadratic Formula:x =  −b ± √(b2 − 4ac)2a

Put in a, b and c:x =  −6 ± √(62 − 4×5×1)2×5

Solve:x =  −6 ± √(36 − 20)10

 x =  −6 ± √(16)10

 x =  −6 ± 410

 x = −0.2 or −1

x = −0.2 or x = −1

Step-by-step explanation:

there you go

check the picture below.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!