Write a sine function that has a midline of 3, an amplitude of 4 and a period of 2π. PLEASE HELP! WILL MARK BRAINLIEST!

y = Asin(Bx-C) + D

D is midline.  A is amplitude.  Period is 2π/|B|  (More useful for graphing and shows the effect of B).  Strictly speaking, the frequency is the inverse of period:  f = |B|/(2π), but a lot of math texts say frequency when they mean angular frequency which is rad/s vs. cycles/sec.  The angular frequency ω = 2πf  (2π rads/cycle) or just |B|.  Finally the function is translated to the right  C/B (to the left if C/B is negative)

Step-by-step explanation:

56

step-by-step explanation:

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.