Tell whether each equation has one, zero, or infinitely many solutions. If the equation has one solution, solve the equation.
11. 6(x - 1) = 6x-1
10. 4(x-2) - 4x + 10
13. 4x + 5 = 9+ 4x 6.
12. 6n + 7-2n-14 = 5n + 1
15. 40-8x + 12) = -26-32x
14.8(y + 4) = 7y + 38

6x-1=6x-1 infintely many

4x-8=4x+10 no solution

4x+5=4x+15 no sloution

4n-7=5n+1 n=-8

-8x+52=-26-32x 24x=78 x= 3 1/4

8y+32=7y+38  y=6

Hope this helps your spelling/typing is a bit off but mark brainliest :D

some of them are wrong bcuz i dont know the real typing :(

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step-by-step explanation:

i used the pitagoras theoreme