Log3(2x-1)=3 help me out:(

x = 2.

Step-by-step explanation:

(Brainliest?)

So log3(2x-1)+log3(x+7)=3 = log3(3^3) So (2x- 1)(x+7) = 27 2x^2+13x - 34 =0 (2x+17)(x - 2) = 0 ..so x = 2 or - 17/2. The solution x = - 17/2 is rejected since we cannot have log 3(2*- 17/2 - 1),a negative number. So the answer is x = 2.

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

i believe it’s 165 because if u add 137 and 58 u get 195 and then subtract that from 360 and there’s ur answer