A truck can be rented from Company A for $70 a day plus $0.20 per mile. Company B charges $20 a day plus $0.40 per mile to rent the same truck. How many miles must be driven in a day to make the rental cost for Company A a better deal than Company B's? For Company A to have a better deal, the truck must be driven more than

blank miles per day.

pls fast

For Company A to have a better deal, the truck must be driven more than 250 miles per day.

Step-by-step explanation:

Given that:

Rent per day of company A = $70

Per mile charges = $0.20

Let,

x be the number of miles.

A(x) = 0.20x + 70

Rent per day of company B = $20

Per mile charges = $0.40

B(x) = 0.40x + 20

For make Company A better deal,

A(x) > B(x)

0.20x+70 > 0.40+20

0.20x-0.40x>20-70

-0.20x>-50

Dividing both sides by -0.20

Hence,

For Company A to have a better deal, the truck must be driven more than 250 miles per day.

560

step-by-step explanation:

giggidy

step-by-step explanation:

to determine whether a given function is even, we simply substitute x with -x in the expression. if the result after simplification is identical to the original equation, then the function is said to be even other wise odd.

f(-x) = (-x)^2 - (-x) + 8

      = x^2 + x +8

the resulting function is not identical to the original one;

f(-x) ≠ f(x)

therefore, f(x) is not an even function