How would I solve this question

Will mark brainlist king

9514 1404 393

  4)  (4, 0)

Step-by-step explanation:

I find it useful to graph the inequalities and the points.

The point on the dashed line is not in the solution set. The only point in the doubly-shaded area is (4, 0), choice (4).

__

Another method of choosing the points is to try them in the inequalities. I find it easier to do the math if the inequalities are written in standard form:

  2y < x +8 . . . . . multiply the first by 2

  x -2y > -8 . . . . . add -8-2y and swap sides. This is the first inequality.

__

  y ≥ -x +1

  x + y ≥ 1 . . . . .  add x. This is the second inequality

__

For the four points in the first inequality, we have ...

  1) -5 -2(3) = -11  . . .  not greater than -8

  2) 0 -2(4) = -8 . . . not greater than -8

  3) 3 -2(-5) = 13 . . . greater than -8, satisfies the first inequality

  4) 4 -2(0) = 4 . . . greater than -8, satisfies the first inequality

__

So, the two points that might possibly work are (3, -5) and (4, 0). Here, we try these in the second inequality.

  3) 3 -5 = -2 . . . less than 1

  4) 4 + 0 = 4 . . . greater than 1, satisfies the second inequality

The only point listed that is a solution to the system is (4, 0), point 4.

the answer to your question is b.