Write the equation of a line in point-slope form that is parallel to the line y=2x-5 and goes through the point (-1,4)

(y-4) = 2(X+1)

Step-by-step explanation:

Hey there!

The given eqaution is; y = 2x-5(i)

Now; As the eqaution is in the form of y= mx+b.

Slope(m1) = 2.

As per the condition of parallel lines, slope of the 1st equation (m1) = slope of 2nd eqaution (m2).

Therefore, m1= m2= 2

Now, use one point formula for finding the eqaution of the line which passes through the point.

(y-y1) = m2(x-x1)

~ Put all values.

(y-4) = 2(X+1)

You can simply write upto here. But it you want to make it simplified form then, (look below)

~ simplify it.

y = 2x +2+4

The eqaution of the line which is parallel to y = 2x -5 and point (-1,4) is y = 2x + 6.

Hope it helps

y - 4  = 2(x + 1)

Step-by-step explanation:

The point slope form formula says that   y - b = m(x-a)  where  m is the slope,b is the y coordinate of a given point , and a  is the x coordinate of the same point.

Remember that parallel lines have the same slopes but different y-intercepts, meaning that  m will equal to 2  because the slope for the line y=2x-5 is 2.

m will be 2, b will be 4 , and  a will be -1.

      y - 4 = 2(x - (-1)     which reduces to  

   y - 4  = 2(x + 1)

for finding the midpoint of any given 2 pair of points simply add the respective x coordinates with other x coordinate and the y coordinate with other y coordinate and divide them by 2

in your question it will be :

(3+1)/2 for the x coordinate of mid point i.e 2

[8+(-4)]/2 for the y coordinate of midpoint i.e 2

so coordinates of mid point of points (3,8) and (1,-4) will be (2,2)