Solve the system of equations below by elimination.
(Show your work)
2x+3y=1
5x+7y=3

-2x+2y+3z=0

-2x-y+z=-3

2x+3y+3z=5

-2x+2y+3z=0

-2x-y+z=-3

Subtract

3y + 2z = 3 Eqn A

-2x-y+z=-3

2x+3y+3z=5

Add

2y + 4z = 2

6y + 4z = 6 Eqn A times 2

Subtract

-4y = -4

y = 1

z = 0

x = 1

walter needs to make at least 5 more cookies but no more than 40. 5 ≥ x ≥ 40;

step-by-step explanation:

walter has to make a minimum of 20 cookies. he already has 15 cookies made, so he must make 5 more to meet the minimum.

the maximum amount of cookies he can make is 55. he already has 15, so he has to make no more than 40 more cookies to meet the maximum.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?