1. Which combined solid did you select? (Circle one.) (1 point) Left: Icosahedron with tetrahedrons
Right: Octahedron with tetrahedrons
Construct the models
Nets are two-dimensional patterns that fold into 3-dimensional shapes, so they are a great tool for analyzing and constructing solids. Use the tetrahedron, octahedron and the icosahedron tools to help you examine each shape more closely, and to practice folding each net into a solid.
2. Using the link on the activity page, cut out each net. Fold and tape each net into a three-dimensional solid. Your solids do not need to be perfect. (9 points: 3 points for each solid)

3. Identify each solid. Hint: count the number of faces you can see. (6 points: 1 point for each blank)

Solid 1: number of faces:_
name of solid: _
Solid 2: number of faces:_
name of solid: _
Solid 3: number of faces:_
name of solid: _

Your solid
4. Look at the polyhedron that you chose at the beginning. Which two solids do you need to create your polyhedron? How many of each solid do you need?

Answer for your polyhedron. Hint: Each tetrahedron will cover one face of the other solid. (4 points: 1 point for each blank)

Polyhedron 1: Solid:_
Number: _
Solid:_
Number: _
Polyhedron 2: Solid:_
Number: _
Solid:_
Number: _

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

step-by-step explanation:

the answer will be b x² +x-1

step-by-step explanation:

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

br

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 =   (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4   we need to find some relationship between a and b.

let's try ab = bc  

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2 

br = sqrt(3) * a

cp

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram. 

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a 

cp = sqrt(3)*a

aq

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a 

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt  3) * a which agrees with the other two.