HELP PLZ ILY

For the first question, x = 12.

For the second question, x = -9

Step-by-step explanation:

In the first question, in △RSQ,

RZ/RS = 1/2 = RY/RQ (given)

∠ZRY = ∠ZRY (common)

∴ △RZY ~ △RSQ (2 sides prop., inc. ∠)

∵ △RZY ~ △RSQ

∴ RZ/RS = RY/RQ = ZY/SQ = 1/2

(x+2) / (3x-8) = 1/2

2(x+2) = (3x-8)

2x + 4 = 3x - 8

3x - 2x = 12

x = 12

In the second question, in △SRT,

SC/SR = 1/2 = SB/ST (given)

∠CSB = ∠CSB (common)

∴ △SCB ~ △SRT (2 sides prop., inc. ∠)

∵ △SCB ~ △SRT

∴ SC/SR = SB/ST = CB/RT = 1/2

(x+19) / (x+29) = 1/2

2(x+19) = (x+29)

2x + 38 = x + 29

2x - x = 29 - 38

x = -9

Step-by-step explanation:

answer: yes, he is correct

step-by-step explanation: 10x-1=59

                                              1-1=0     59+1=60

60/10=x=6

45.3592

step-by-step explanation: