Write the quadratic variation equation for the relationship: y varies directly with x2 and y = 36 when x = 3.
a. y = ¼x^2
b. y = 12x
c. y = 4x^2
d. y = x^2 + 25

The answer is C. y = 4x^2

y varies directly with x2 can be expressed as:
y = k*x²

When x = 3, they y = 36. And you just need to replace it in the equation from above:
36 = k*3²
36 = k*9
⇒ k =36/9 = 4

So, the related equation is
y = 4x²

Step 1: 6x-10=1; step 2: 6x=11