Question is: a park in a subdivision is triangular-shaped. two adjacent sides of the park are 533 feet and 525 feet. the angle between the sides is 53 degrees. find the area of the park to the nearest square foot.

i thought this was what i was suppose to do.

1/2 * 533 * 525 * sin (53)

Step-by-step explanation:

we know that

The area of a triangle is equal to

where

a,b are two adjacent sides of the triangle

C is the angle between the two sides adjacent

In this problem we have

substitute

mark brainliest

step-by-step explanation:

2 tens + 6 ones

1 ten + 16 ones

0 tens + 26 ones

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i