What is the equation of the line through the origin and (2,5)? A. y = 5/2x
B. y = 2/5x
C. y= 2x
D. y = 5x

A

Step-by-step explanation:

We can just use the slope equation here.

The two given points are (0,0) and (2,5)

Since the line intersects the y-axis at the origin, the y-intercept is 0.

So, our slope-intercept equation is .

Hope this helps!

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15