Find the equation of a straight line that passes through the points(-2,10) and (4,14)

y = x + 11

Step-by-step explanation:

The equation of a straight line is: y = mx+c where m is the slope of the line and c is the y-intercept of a line.

Slope =

          =

          =

          =

To find the y-intercept, we can use one of the points to apply for the equation before finding the y-intercept. I will be using the point (4,14).

y = x + c

14 = ×4 + c

14 = 2 + c

c = 14-2

c = 11

Thus, the y-intercept is 11.

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !