A quadratic function y=f(x)y=f(x) is plotted on a graph and the vertex of the resulting parabola is
(−4,6)
(−4,6). What is the vertex of the function defined as
g(x)=f(−x)−4
g(x)=f(−x)−4?

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

no not all of them.

step-by-step explanation:

some of them have a square base.