The equation $y+4x=100$y+4x=100 represents your distance y (in meters) from the finish line x seconds after you begin your leg of a relay race. The equation $y+3.7x=94$y+3.7x=94 represents your opponent's distance from the finish line. How far do you need to run to catch up with your opponent?

Given:

Your distance y (in meters) from the finish line x seconds after you begin your leg of a relay race is

Opponent's distance is

To find:

The distance you need to run to catch up with your opponent.

Solution:

We have,

           ...(i)

         ...(ii)

Subtract (ii) from (i), we get

Divide both sides by 0.3.

Put x=20 in (i).

They will meet at (20,20). It means at 20 meters from the finish line after 20 seconds from the beginning.

Put x=0 in (i), we get

It means, initially the total distance you and finish line is 100 meters.

You will catch your opponent 20 meter from the finish line. So,

Therefore, you need to run 80 meters to catch up with your opponent.

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

nope

step-by-step explanation: