Emilio throws a marshmallow into the air from his balcony. The height of the marshmallow (in feet) is represented by the equation h=−16(t−14)2+49, where t is the time (in seconds) after he throws the marshmallow. How long after Emilio throws the marshmallow does it reach its maximum height?

Step-by-step explanation:

−16t^2+8t+48 = 0

- 2t^2 + t + 6 = 0

Multiplying through by the negative sign. It becomes

2t^2 - t - 6 = 0

2t^2 + 3t - 4t - 6 = 0

t(2t + 3) - 2(2t + 3) = 0

(t - 2)(2t + 3) = 0

t - 2 = 0 or 2t + 3 = 0

t = 2 or t = - 3/2

The time cannot be negative

So it will take 2 seconds to hit the ground

answer:   (s+1)(s+4)

step-by-step explanation:

factor s2+5s+4

s2+5s+4

=(s+1)(s+4)

1. a^4+8a^3+24a^2+32a+16

2.y^8+8y^7+28y^6+56y^5+70y^4+56y^3+28y^2+8y+1

3.x^6-3x^4y^2+3x^2y^4-y^6