Find three consecutive odd integers such that the product of the first two is equal to one more than twice the third

or

Step-by-step explanation:

Let first consecutive odd integer =

Second consecutive odd integer =

Third consecutive odd integer =

"Product of the first two is equal to one more than twice the third" can be written as:

(expand brackets)

(combine like terms)

∴ Consecutive integers =  or

Hope this helps :)

687.09 dollars       happy now

step-by-step explanation: 6870

1857 times .63 equals 1169.91 subtract that from 1857 you get 687.09

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.