A cycling race is 17 miles long. The cyclists will begin at point S and ride a number of laps around a neighborhood block. After the last lap, the cyclists will sprint 2.0 miles to the finish line. A rectangle with a width of 0.75 miles and height of 0.5 miles. The 2 mile finish comes out of one corner. Using the equation w (1.5 + 1) + 2 = 17, the race’s organizer determined the cyclists will need to ride 9 laps before the sprint to the finish. Which explains the error? The equation should be 0.75 w + 0.5 w + 2 = 17, and the cyclists will need to ride 12 laps before the sprint to the finish. The equation should be 2 (0.75 w + 0.5) + 2 = 17, and the cyclists will need to ride 21 laps before the sprint to the finish. The solution should be 6, and the cyclists will need to ride 6 laps before the sprint to the finish. The solution should be 8, and the cyclists will need to ride 8 laps before the sprint to the finish.

29 mil

step-by-step explanation:

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.