Complete the square to solve the equation below. x² + 2x-7= 17
A. x = -1, x = 4
O B. X=-6, x = 4
O C. X=-1, x = 3
O D. x = 5, x= -4
SUBM

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  B.  x = -6, x = 4

Step-by-step explanation:

The constant on the left wants to be 1, the square of half the x-coefficient. We can get it to be that value by adding 8 to the equation.

  x² +2x +1 = 25

  (x +1)² = 25 . . . . . . . rewrite the left side as a square

  x +1 = ±√25 = ±5 . . . . take the square root

  x = -1 ±5 . . . . . . . . . subtract 1

  x = -6 or x = 4

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)