At time 0, John has $2. At times 1, 2, . . ., he independently plays a game in which he bets $1. With probability p = 0.49, he wins the game and with probability 1 − p = 0.51, he loses the game. His goal is to increase his capital to $3, and as soon as he does, the game is over. The game is also over if his capital is reduced to zero. Construct an absorbing Markov chain and answer the following questions. • What is the expected duration of the game? •

What is the probability that he goes broke?

  the correct choice is marked

step-by-step explanation:

the first two graphs show multiple turning points. the last graphs matches the description in every detail.

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00

98%

step-by-step explanation:

idk

step-by-step explanation:

payback