Elevator #1 starts moving upward from a height of 28 feet at a rate of 8 feet per second. At the same time, elevator #2 starts moving downward from a height of 100 feet at a rate of 10 feet per second. Part 1

Which two equations form a system that can be solved to find how many seconds (s) it will take for both elevators to reach the same height (h) in feet?
When the elevators reach the same height, how many feet high will they be? (Use the digits 0 – 9 to enter the number. Use a decimal point only if needed.)

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step-by-step explanation:

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x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

let y equal to

the total fare and x is the mile of taxi ride. so the equation is

y = 0.55x + 1.75

since susie has

$10 to spend for a taxi cab, so he can have

10 = 0.55x +

1.75

x = 15 miles of

taxi ride

so the system of

inequality is

10 < 0.55x +

1.75

x > 2