Consider the following quadratic function and its graph. f(x) = x2 – 4x – 21 On a coordinate plane, a parabola opens up. It goes through (negative 4, 8), has a vertex around (2, negative 21), and goes through (8, 8). What is the solution of the following quadratic inequality? x2 – 4x – 21 ≤ 0

i dont know i just need points

yess

step-by-step explanation:

idk whyy this is happening, i cant even read my notification bc i keep getting errors

~coco

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl