A random sample of size 64 was obtained which had sample mean of 1.03 and sample standard deviation of 0.189. Find the P-value.

The P-value is 80.23%

Step-by-step explanation:

Given;

number of samples, n = 64

sample mean, X = 1.03

standard deviation, σ = 0.189

Population mean (μ) is given as;

The z-score is given as;

z ≅ 0.85

From the z-table, the P-value at the given z-score is 0.8023 = 80.23%;